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Mathematics
Hayden Glenn
24 May, 18:35
2 (x+y) = 61-2y
4x-4 = 18-3y
+4
Answers (
1
)
Emery Riddle
24 May, 20:22
0
x = 8
y = - 7
Step-by-step explanation:
This is a system of equations called simultaneous equations. We shall solve it by elimination method Step 1We shall label the equations (1) and (2) - 3y-4x=-11 ... (1) 3y-5x=-61 ... (2) Step 2Multiply each term in equation (1) by 1 to give equation (3) 1 (-3y-4x=-11) ... (1) - 3y-4x=-11 ... (3) Step 3Multiply each term in equation 2 by - 1 to give equation (4) - 1 (3y-5x=-61) ... (2) - 3y+5x=61 ... (4) Step 4-3y-4x=-11 ... (3) - 3y+5x=61 ... (4) Subtract each term in equation (3) from each term in equation (4) - 3y - (-3y) + 5x - (-4x) = 61 - (-11) - 3y+3y+5x+4x=61+110+9x=729x=72Step 5Divide both sides of the equation by 9, the coefficient of the unknown variable x to find the value of x 9x/9 = 72/9x = 8Step 6Put in x = 8 into equation (2) 3y-5x=-61 ... (2) 3y-5 (8) = -613y-40=-61Collect like terms by adding 40 to both sides of the equation 3y-40+40=-61+403y=-21Divide both sides by 3, the coefficient of y to find the value of y 3y/3=-21/3y=-7Therefore, the values of x and y that satisfy the equations are 8 and - 7 respectively
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