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3 February, 11:27

3^x=9^x+5 what does x equal

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  1. 3 February, 12:52
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    So you have to find the common base first which in this case is 3:

    3^x = (3^2) ^x+5

    so now we can multiply the exponents on the right side of the equation:

    3^x=3^2x+10

    Now we can isolate the exponents to solve for x:

    x=2x+10

    subtract 2x from both sides

    -x=10

    divide the - on both sides

    x = - 10

    so the answer is

    x = - 10
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