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23 March, 06:13

Determine the factors of 4x2 5x - 6 a (4x - 2) (x 3) b (4x - 3) (x 2) c (4x - 6) (x 1) d (4x - 1) (x 6)

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  1. 23 March, 09:13
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    4x^2 + 5x - 6 = (4x - 3) (x + 2)

    You can do it by using the quadratic function to solve 4x^2 + 5x - 6 = 0; the result will be x = 3/4 and x = - 2

    Then you have to make (x - 3/4) = 0 and (x + 2) = 0

    When you develop x - 3/4 = 0 you get 4x - 3 = 0, which means that 4x - 3 is a factor. The other factor is directly x + 2.

    Answer: option b: (4x - 3) (x + 2)
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