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Mathematics
Alonzo Bass
30 November, 12:42
Create a pattern with the rule n*2+1
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Malakai Macias
30 November, 16:36
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The rule (n*2+1) gives the sequence of odd numbers { ..., - 5, - 3, - 1, 1, 3, 5, ... }.
Step-by-step explanation:
We have the expression 'n*2+1'.
It is required to find a pattern obtained by the expression.
Substituting values of 'n' gives,
For n = - 3, we get (n*2+1) = (-3*2+1) = - 6+1 = - 5
For n = - 2, we get (n*2+1) = (-2*2+1) = - 4+1 = - 3
For n = - 1, we get (n*2+1) = (-1*2+1) = - 2+1 = - 1
For n = 0, we get (n*2+1) = (0*2+1) = 1
For n = 1, we get (n*2+1) = (1*2+1) = 2+1 = 3
For n = 2, we get (n*2+1) = (2*2+1) = 4+1 = 5
So, we see that, substituting the value of n, the result comes out to be an odd number.
Hence, the rule (n*2+1) gives the sequence of odd numbers { ..., - 5, - 3, - 1, 1, 3, 5, ... }.
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