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16 June, 03:14

A true-false question is to be posed to a husband and wife team. Both the husband and the wife will give the correct answer with probability 0.8. Which of the following is a better strategy for the couple? Strategy 1: choose one of them at random and ask the chosen person to answer the question Strategy 2: have them both answer the question. If their answers agree, give the common answer; if they disagree, flip a fair coin to determine which answer to given.

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  1. 16 June, 06:32
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    Choose either strategy both are equally successful

    Step-by-step explanation:

    Given:-

    - The probability of success for both husband (H) and wife (W) are:

    P (W) = 0.8, P (H) = 0.8

    Find:-

    - Which of the following is a better strategy for the couple?

    Solution:-

    Strategy 1

    - First note that P (W) & P (H) are independent from one another, i. e the probability of giving correct answer of husband does not influences that of wife's.

    - This strategy poses an event such that either wife knows the answer and answer it correctly or the husband knows and answers in correctly.

    - We will assume that probability of either the husband or wife knowing the answer is 0.5 and the two events of knowing and answering correctly are independent. So,

    P (Wk) = P (Hk) = 0.5

    - The event P (S1) is:

    P (S1) = P (Hk & H) + P (Wk & W)

    P (S1) = 0.5*0.8 + 0.5*0.8

    P (S1) = 0.8

    - Hence, the probability of success for strategy 1 is = 0.8

    Strategy 2

    - Both agree, then the common answer is selected otherwise, one of their answers is chosen at random.

    - The success of strategy 2, will occur when both agree and are correct, wife is correct and answers while husband is not or husband is correct and he answers.

    - The event P (S2) is:

    P (S2) = P (H & W) + P (H / W' & Hk) + P (H' / W & Wk)

    P (S2) = P (H & W) + P (H / W') P (Hk) + P (H' / W) P (Wk)

    P (S2) = P (H & W) + P (H / W') * 0.5 + P (H' / W) * 0.5

    P (S2) = 0.5 * [ P (H & W) + P (H / W') ] + 0.5 * [ P (H' / W) + P (H & W) ]

    P (S2) = 0.5*P (H) + 0.5*P (W)

    P (S2) = 0.5*0.8 + 0.5*0.8

    P (S2) = 0.8

    - Hence, the probability of success for strategy 2 is = 0.8

    Both strategy give us the same probability of success.
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