An empty 5 gallon water jug weighs 0.75 lbs. With 3 cups of water inside, the jug weighs 2.25 lbs. What equation models the jug's weight y when it contains x cups of water?

Answer: jugs weight ⇒ y = 0.75 + 0.5 x

Step-by-step explanation:

Hi, to solve this problem we have to analize the information given.

So:

Empty jug weight = 0.75 lbs

jug with 3 cups of water weight = 2.25

The next step is to subtract the weight of the empty jug to the weight of the jug with 3 cups.

2.25 - 0.75 = 1.5 lbs

We have calculated the weight of 3 cups of water. To calculate the weight of one cup we simply divide the result by 3.

1.5 / 3 = 0.5 lbs (1 cup)

Finally, we have the information needed for the equation. It wiil be the weight of the empty jug plus the weight of one cup of water multiplied by x.

jugs weight (y) = 0.75 + 0.5 x

Feel free to ask for more if it's necessary or if you did not understand something

Step-by-step explanation:

3 cups of water + jug = 2.25 lbs

jug =.75 lbs

3 cups of water = 1.5 lbs

1 cup of water =.5 lbs

Therefore,

y =.75 +.5x