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5 July, 15:00

To cover a distance of 240 km has to increase a speed of 5 per hour to reach in time time. If the time Lost was 40 minutes during traffic find the original speed

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  1. 5 July, 16:20
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    The initial speed is approximately 104.3 km

    Step-by-step explanation:

    Let Distance = 240 km

    Time = ?

    Speed =

    Since

    Speed = Distance/Time

    Distance = Speed * Time

    When arrival is late:

    240 = S*T

    When arrival is on time:

    240 = (S+5) * T2

    But 40minutes = 2/3 hours

    So,

    T2 = T - 2/3

    240 = (S+5) * (T - 2/3)

    240 = ST - 2S/3 + 5T - 10/3

    ST - 2S/3 + 5T = 240 + 10/3

    S (T - 2/3) + 5T = 730/3

    S (T - 2/3) = 730/3 - 5T

    S = (730/3 - 5T) / (T - 2/3)

    But 240 = ST

    S = 240/T

    240/T = (730/3 - 5T) / (T - 2/3)

    (T - 2/3) / T = (730/3 - 5T) / 240

    1 - 2/3T = 730/720 - 5T/240

    1 + 73/72 = (2/3 + 5/24) T

    145/72 = (7/8) T

    T = 145/72 * 8/7

    = 1160/504

    T = 145/63

    S = 240/S

    = 240*63/145

    = 3024/29

    ≈ 104.3km
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