Ask Question
31 August, 03:56

Two cyclist leave towns 78 miles apart at the same time and travel toward each other. One cyclist travels 5 mi/h faster than the other. If they meet in 2 hours, what is the rate of each cyclist?

+2
Answers (1)
  1. 31 August, 04:13
    0
    One cyclist travels at 17 m/h and the other at 22 m/h.

    Step-by-step explanation:

    Let one cyclist travel at x m/h and the other at (x+5) m/h.

    Their combined speed is x + x + 5 = 2x+5 m/h.

    When they meet the total distance they have travelled will be 78 miles.

    Speed = distance / time taken, so:

    2x+5 = 78/2

    2x + 5 = 39

    2x = 34

    x = 17 m/h = speed of one cyclist.

    So the other travels at 17+5 = 22 m/h.
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “Two cyclist leave towns 78 miles apart at the same time and travel toward each other. One cyclist travels 5 mi/h faster than the other. If ...” in 📙 Mathematics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers