 Mathematics
30 March, 03:14

# A race car driving under the caution flag at 80 feet per second begins to accelerate at a constant rate after the warning flag. The distance traveled since the warning flag in feet is characterized by 30t 2 + 80t, where t is the time in seconds after the car starts accelerating again. How long does it take the car to travel 30 feet after it begins accelerating?

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Answers (1)
1. 30 March, 05:06
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Answer: 1/3 sec or 0.333 sec

Step-by-step explanation:

d = 30*t^2 + 80*t = 30

putting into quadratic form, a*t^2 + b*t + c = 0

30*t^2 + 80*t - 30 = 0 where: a = 30 b = 80 c = - 30

solve quadratic:

t = [-b + sqrt (b^2 - 4*a*c) ]/2*a

substitute in values above

therefore, t = 1/3 sec or 0.333 sec
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