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30 March, 03:14

A race car driving under the caution flag at 80 feet per second begins to accelerate at a constant rate after the warning flag. The distance traveled since the warning flag in feet is characterized by 30t 2 + 80t, where t is the time in seconds after the car starts accelerating again. How long does it take the car to travel 30 feet after it begins accelerating?

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  1. 30 March, 05:06
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    Answer: 1/3 sec or 0.333 sec

    Step-by-step explanation:

    d = 30*t^2 + 80*t = 30

    putting into quadratic form, a*t^2 + b*t + c = 0

    30*t^2 + 80*t - 30 = 0 where: a = 30 b = 80 c = - 30

    solve quadratic:

    t = [-b + sqrt (b^2 - 4*a*c) ]/2*a

    substitute in values above

    therefore, t = 1/3 sec or 0.333 sec
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