Use the discriminant to determine how many real number solutions exist for the quadratic equation - 4j2 + 3j - 28 = 0. A. 3 B. 2 C. 0 D. 1

C. 0

Step-by-step explanation:

-4j^2 + 3j - 28 = 0

The discriminant is b^2-4ac if >0 we have 2 real solutions

=0 we have 1 real solutions

<0 we have 2 imaginary solutions

a = - 4, b = 3 c = - 28

b^2 - 4ac

(3) ^2 - 4 (-4) * (-28)

9 - 16 (28)

9 - 448

This will be negative so we have two imaginary solutions.

Therefore we have 0 real solutions