Ask Question
25 January, 09:43

X^3 + 5x^2 - 8x^2 - 40x + 7x + 35

+5
Answers (1)
  1. 25 January, 11:06
    0
    Remark

    x - 1 is a root.

    Proof

    x - 1 = 0

    x = 1

    (1) ^3 + 5 (1) ^2 - 8 (1) ^2 - 40 (1) + 7 (1) + 35

    1 + 5 - 8 - 40 + 7 + 35

    6 + 7 + 35 - 48 = 0

    Solution

    Divide x - 1 into the original equation.

    x^3 + 5x^2 - 8x^2 - 33x + 35

    x - 1 || x^3 - 3x^2 - 33x + 35 || x^2 - 2x - 35

    x^3 - x^2

    -2x^2 - 33x

    -2x^2 + 2x

    - 35x + 35

    -35x + 35

    0

    x^2 - 2x - 35 factors into (x - 7) (x + 5)

    Complete factorization

    (x - 1) (x - 7) (x + 5)
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “X^3 + 5x^2 - 8x^2 - 40x + 7x + 35 ...” in 📙 Mathematics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers