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18 January, 15:57

The admission at an ice hockey game is 8$ for adults and 5$ for children. A total of 330 tickets were sold. How many tickets were sold to children and how many to adults if a total of 2244$ was collected?

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  1. 18 January, 18:44
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    Answer: A total of 132 tickets were sold to children and 198 tickets were sold to adults

    Step-by-step explanation: Let the adult's tickets be called x and the children's tickets be called y.

    If a total of 330 tickets were sold in all, that means x and y totaled 330, or we can express this as

    x + y = 330

    Also if each adult ticket is $8 and each child ticket is $5, and the total sales was $2244, then it means the total of x tickets times $8 plus total of y tickets times $5 would be equal to 2244. In other words,

    8x + 5y = 2244

    We now have a pair of simultaneous equations as follows

    x + y = 330 - - - (1)

    8x + 5y = 2244 - - (2)

    From equation (1) we make x the subject of the equation and we have

    x = 330 - y

    Substitute for the value of x into equation (2)

    8 (330 - y) + 5y = 2244

    2640 - 8y + 5y = 2244

    By collecting like terms we now have

    2640 - 2244 = 8y - 5y

    396 = 3y

    Divide both sides of the equation by 3

    132 = y

    Having calculated the value of y, substitute for the value of y into equation (1)

    x + y = 330

    x + 132 = 330

    Subtract 132 from both sides of the equation

    x = 198

    Therefore, the total adult tickets (x) sold was 198.

    And the total of children's tickets (y) sold was 132.
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