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14 October, 07:40

a metal worker has a metal alloy that is 20% copper, and another metal alloy that is 60% copper. How many kilograms (kg) of each allow should the metal worker combine to create 80kg of aa 52% copper alloy?

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  1. 14 October, 09:05
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    Let X = the 29% alloy and Y = the 60% alloy.

    They want a total of 80kg, so you have X + Y = 80

    Rewrite that to get X = 80-Y

    You also want 0.20X + 0.60Y = 0.52 (80)

    Replace X with 80-y:

    0.20 (80-y) + 0.60y = 0.52 (80)

    Simplify:

    16 - 0.20y + 0.60y = 41.6

    Combine like terms:

    16 + 0.40y = 41.6

    Subtract 16 from each side:

    0.40y = 25.6

    Divide both sides by 0.40

    y = 25.6 / 0.40

    y = 64

    Now you have Y replace y with 80 in X = 80-Y

    X = 80 - 64

    X = 16

    They need 64 Kg of the 60% alloy and 16 Kg of the 20% alloy.
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