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11 January, 18:37

Between what two integers does √98 lie?

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Answers (2)
  1. 11 January, 19:34
    0
    one way is this:

    if the 2 integers are x and y, then

    x<√98
    if we assume that x and y aer both positive then

    square everybody

    x²<98
    solve each

    x²<98

    square root both sides

    x<9.89

    since x must be an integer, x=9

    98
    squaer root both side

    9.89
    since y must be an integer, y=10

    √98 lies between 9 an 10
  2. 11 January, 20:11
    0
    Which perfect square is less than 98? More than 98?

    9^2 = 81, and 10^2 = 100.

    Since 81 < 98 < 100,

    √81 < √98 < √100.

    Therefore, 9 < √98 < 10∫

    √98 lies between the integers 9 and 10.
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