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16 October, 14:15

Attorney A charges a fixed fee on $250 for an initial meeting and $150 per hour for all hours worked after that. Write an equation in slope-intercept form. Attorney B charges $150 for the initial meeting and $175 per hour. Find the charge for 26 hours of work for each attorney. Which is the better deal? At how many hours does this attorney become a better deal?

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  1. 16 October, 14:33
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    let h be the number of hours then

    A → C = 150h + 250 (where C is charge)

    B → C = 175h + 150

    for 26 hours

    A → C = (150 * 26) + 250 = 3900 + 250 = $4150

    B → C = (175 * 26) + 150 = 4550 + 150 = $4700

    Attorney A is cheaper for 26 hours, thus better deal

    Equate the 2 equations to find hours they charge the same

    175h + 150 = 150h + 250 (subtract 150h from both sides)

    25h + 150 = 250 (subtract 150 from both sides)

    25h = 100 (divide both sides by 25)

    h = 4 ← number of hours when charges for both are equal

    Thus Attorney A becomes a better deal at 5 hours
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