Suppose that 37.4% of all college football teams had winning record in 1998, and another 24.8% broke even (aka, they won the same number of games that they lost). What is the probability that a randomly chosen college football team had a losing record in 1998?

Question

Mathematics

Buffie

11 August, 03:41

Suppose that 37.4% of all college football teams had winning record in 1998, and another 24.8% broke even (aka, they won the same number of games that they lost). What is the probability that a randomly chosen college football team had a losing record in 1998?

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Answers (1)

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Lynx · Answer 1

Probability of losing P (l) = 0.378 or 37.8%

Step-by-step explanation:

Given:

Probability of winning P (w) = 37.4% = 0.374

Probability of broke even P (b. e) = 24.8% = 0.248

Find:

Probability of losing P (l) = ?

Computation:

Probability of winning + Probability of broke even + Probability of losing = 1

0.374 + 0.248 + Probability of losing P (l) = 1

Probability of losing P (l) = 1 - 0.374 - 0.248

Probability of losing P (l) = 0.378 or 37.8%

Therefore, Probability of losing is 37.8%