26. Find the area of a regular hexagon whose side length is 16 in, and the apothem is 8 3 in.

384 / 3 in?

256/5 in

128/3 in?

64 / 3

Apothem=8rt3 in Half of one side=8 in Since the apothem, half-side, and segment extending from the center to the vertex form a right triangle, you have the length and height and can calculate the area. (8 * 8rt3) / 2 = 32 in square. There are 12 of these triangles so multiply that by 12. You get 384rt3 inches square.