Given sinθ=4/7 and θ lies in Quadrant II.

What is the exact value of cosθ in simplified form?

-4√33/33

-√33/4

√33/7

-√33/7

Answer:-√33/7

Step-by-step explanation:

Second quadrant implies cos negative, as cos is projection from

unit circle to x axis.

sin^2+cos^2=1

cos = sqrt (1-sin^2)

sin^2 = 16/49

1-sin^2 = 33/49

sin = - sqrt (33) / 7