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13 January, 01:16

Y varies directly with the square of X. If y = 5 when x=3, what is the value of y when x=9?

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  1. 13 January, 01:43
    0
    Answer:45

    Step-by-step explanation:

    y varies directly as x^2

    y=k x x^2

    When y=5 x=3

    5=k x 3^2

    5=k x 9

    K=5/9

    Relationship is y=5x^2/9

    y = (5x9^2) ➗ 9

    y = (5x81) ➗ 9

    y=405 ➗ 9

    y=45
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