You have a cone with a radius of 8 ft and a height of 10 ft. Find the area of the triangle formed by a perpendicular cross-section through the cone's center.

80ft²

Step-by-step explanation:

Given in the question,

radius of cone's base = 8ft

cone's base = base of triangle

height of cone = 10 ft

height of cone = height of triangle

Area of triangle

Area = 1/2 (h) (b)

here h = height of triangle

b = base of triangle

A = 1/2 (8) (10)

A = 40ft²

Since the section is 2 similar triangles back to back around the vertical centre so the area cross sectional area of triangle form in the cone is 2 (40) ft² = 80ft²