Moore's law says that the number of transistors in a dense integrated circuit increases by 41/%41%41, percent every year. In 197419741974, a dense integrated circuit was produced with 500050005000 transistors. Which expression gives the number of transistors in a dense integrated circuit in 197919791979?

Question

Mathematics

Slinky

22 June, 01:09

Moore's law says that the number of transistors in a dense integrated circuit increases by 41/%41%41, percent every year. In 197419741974, a dense integrated circuit was produced with 500050005000 transistors. Which expression gives the number of transistors in a dense integrated circuit in 197919791979?

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Daniella · Answer 1

In 1979 the amount of transistors in a chip was approximately 27865.

Step-by-step explanation:

Since the number of transistors in 1974 was 5000 per chip and it increases at a rate of 41% per year, the number of transistors in a chip per year can be modelled by the following expression:

chips (t) = 5000 * (1.41) ^ (t - 1974)

Therefore in 1979, we have:

chips (1979) = 5000 * (1.41) ^ (1979 - 1974)

chips (1979) = 5000 * (1.41) ^5

chips (1979) = 27865.4183

In 1979 the amount of transistors in a chip was approximately 27865.