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27 November, 14:19

Completely factor 4a^2-12a+8

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Answers (2)
  1. 27 November, 16:30
    0
    4 (a-1) (a-2)

    Step-by-step explanation:

    take out 4 (common factor)

    4 (a^2-3a+2)

    then use box method to factor

    a - 1

    a a^2 - a

    -2 - 2a 2

    4 (a-1) (a-2)
  2. 27 November, 16:55
    0
    4 (a - 2) (a - 1)

    Step-by-step explanation:

    4a^2 - 12a + 8 =

    First, factor out a common factor from all terms.

    = 4 (a^2 - 3a + 2)

    To factor a^2 - 3a + 2, you need two numbers whose product is 2 and whose sum is - 3. Since the product is a positive number, 2, the two numbers are either both positive or both negative. Since the sum is negative, - 3, then both numbers must be negative. The two numbers are - 1 and - 2.

    = 4 (a - 2) (a - 1)
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