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Mathematics
Elvis Flowers
27 January, 22:43
What are the zeros of f (x) = x^2-8x+15
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Bell
27 January, 23:41
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The zeros are x=5 and x=3
Step-by-step explanation:
x^2-8x+15
To find the zeros, we set the equation equal to zero
x^2-8x+15 = 0
Factor the equation
What 2 numbers multiply to 15 and add to - 8
-5*-3 = 15
-5+-3 = - 8
(x-5) (x-3) = 0
Using the zero product property
x-5 = 0 x-3 = 0
x=5 x=3
The zeros are x=5 and x=3
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