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1 December, 20:43

Solve 5|x-3|-8≥2 and give the final answers that would make the equation true

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  1. 1 December, 22:55
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    Ok so oadd 8 to both sides

    5|x-3|≥10

    divide both sides by 5

    |x-3|≥2

    now assume negative and positive and don't forget to flip sign

    x-3≥2 and x-3≤-2

    x-3≥2

    add 3

    x≥5

    x-3≤-2

    add 3

    x≤1

    x≤1 and x≥5
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