How do you put y=-3 (x-4) ^2-10 in standard form?

Question

Mathematics

Melany Gamble

24 March, 11:03

How do you put y=-3 (x-4) ^2-10 in standard form?

+4

Answers (2)

Know the Answer?

Dereon Berger · Answer 1

y=-3x^2 + 24x - 58

Step-by-step explanation:

You first distribute the - 3 by multiplying it to x and - 4. Then just add the exponent.

Yasmine Boyle · Answer 2

y = - 3x² + 24x - 58

Step-by-step explanation:

You distribute out the root and simply it.

y = - 3 (x-4) ² - 10

y = - 3 (x² - 8x + 16) - 10

y = - 3x² + 24x - 48 - 10

y = - 3x² + 24x - 58