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5 August, 09:49

Find a number less than 100 that is increased by one-fifth of its value when its digits are reversed.

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  1. 5 August, 11:45
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    Lets say the number is ab. Its value is 10a + b

    When it is reversed it is 10b + a = 12a+1.2b (from the condition its value should increase 0.2 times).

    11 a = 8.8b

    a/b = 8.8/11 = 0.8/1 = 8/10 = 4/5 (we do this because a and b should be natural numbers less than 10).

    answer is 45.
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