Find the x-intercepts of the parabola with vertex (-7,45) and y-intercept (0,-200). Write your answer in this form: (x1, y1), (x2, y2). If necessary, round to the nearest hundredth.

Step-by-step explanation:

bit lengthy but ...

we know vertex is equal (h, k)

h=x. k=y

the vertex formula is f (x) = a (x-h) ^2+k

lets plug in vertex ... a (x+7) ^2+45

we need to solve for (a) in order to make sure this will pass thru the coordinate (0,-200) and then from there we can get our x int.

the way we solve for a is to set the equation equal to the y int (-200)

f (x) = a (x+7) ^2+45=-200

lets set x=0 because we already set y=-200

a (0+7) ^2+45=-200

a (7) ^2+45=-200

49a+45=-200

49a=-245

a=-5

Now lets rewrite the vertex form formula with a leading coefficient of - 5

-5 (x+7) ^2+45

now graph this formula verify that it does indeed intersect (0.-200)

then check the table for your zeros or x int you will see that they are

(-10,0) and (-4,0)

or x+10=0 and x+4=0