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18 July, 00:02

Determine the greatest intergral value of K for which 2x^2 - Kx + 2 = 0 will have non-real roots ... Use quadratic inequalities to determine the solution

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  1. 18 July, 01:19
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    Greatest integral value of K = 3.

    Step-by-step explanation:

    The nature of the roots of a quadratic equation is determined by the sign of the discriminant, b^2 - 4ac. For non-real roots this is negative.

    2x^2 - kx + 9 = 0

    The discriminant = (-k) ^2 - 4*2*2, so:

    k^2 - 16 < 0 for non-real roots.

    k^2 < 16

    k < √16

    k < 4

    So the answer is 3.

    The greatest integral value is 8.
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