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13 September, 07:28

Solve the question 2w^2-8w-1 = (w-2) ^2

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  1. 13 September, 07:59
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    w = 7/4 + 1/4 √89 OR w = 7/4 - 1/4 √89

    Step-by-step explanation:

    2w^2-8w-1 = (w-2) ^2

    Multiply (w-2) ^2 by (-1)

    2w^2-8w-1 = - w+2^2

    Add w to both sides

    2w^2-7w-1 = 4

    Add 1 to both sides therefore that - 1 cancels

    2w^2-7w=5

    Get the equation equal to 0 by subtracting 5 from both sides

    2w^2-7w-5=0

    Use the quadratic formula to solve

    x = - (-7) plus or minus √ (-7) - 4 (2) (-5) / 2 (2)

    7 plus or minus √89/4
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