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12 June, 18:41

A coffee mixture contains beans that sell for $0.08 per pound and $0.32 per pound. If 110 pounds of beans create a mixture that sells for $0.27 per pound, to the nearest tenth of a pound, how much of each bean is used in the mixture? Model the scenario with an equation and solve. Use complete sentences to explain whether or not your solution is reasonable.

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  1. 12 June, 18:48
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    Let x = amt of 5.50 per lb coffee

    then

    (200-x) = amt of 3.25 per lb coffee

    ;

    5.50x + 3.25 (200-x) = 4.49 (200)

    :

    5.5x + 650 - 3.25x = 898

    :

    5.5x - 3.25x = 898 - 650

    :

    2.25x = 248

    x =

    x = 110.222 ~ 110 lb of $5.50 coffee

    and

    200 - 110.222 = 89.77 ~ 90 lb of $3.25 coffee
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