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18 May, 13:52

A local hamburger shop sold a combined total of 763 hamburgers and cheeseburgers on Saturday. There were 63 more cheeseburgers sold than hamburgers. How many hamburgers were sold on Saturday?

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  1. 18 May, 17:20
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    In order to solve this we'll start by assigning variables to hamburgers and cheeseburgers, since these are what we're trying to find. Lets say x = hamburgers and y = cheeseburgers. So we know two things, we know that x+y = 763 (hamburgers plus cheeseburgers sold equals 763, and we know that y = x+63 (cheeseburgers sold equals 63 more than hamburgers sold). Now we have a system of equations. This can be solved most easily by rearranging each equation to each y, and then set them equal to each other:

    x+y=763 - > y=763-x, and we already have y=x+63. Set them equal to each other:

    x+63 = 763-x (add x to both sides) - > 2x+63 = 763 (subtract 63 from both sides) - > 2x = 700 (divide both sides by 2) x = 350. So we solved for x, which is hamburgers sold, which is what the question asks for, so your answer is 350 hamburgers were sold on Saturday
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