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26 August, 15:02

Write the quadratic variation equation for the relationship: y varies directly with x2 and y = 36 when x = 3.

A. y = ¼x^2

B. y = 12x

C. y = 4x^2

D. y = x^2 + 25

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  1. 26 August, 17:12
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    The answer is C. y = 4x^2

    y varies directly with x2 can be expressed as:

    y = k*x ²

    When x = 3, they y = 36. And you just need to replace it in the equation from above:

    36 = k*3²

    36 = k*9

    ⇒ k = 36/9 = 4

    So, the related equation is

    y = 4x²
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