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4 October, 02:53

How many real solutions does y = (-x + 4) ^2 have?

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Answers (2)
  1. 4 October, 03:24
    0
    Short answer 1

    Comment

    There are a couple of ways of doing this to show there there is just one solution. The most easily done way is to graph the quadratic. I have done that for you.

    Notice that the quadratic touches the x axis, it does not cut it in two places or no places. When a quadratic just touches the x axis, it has only one solution.

    Method 2

    The quadratic is shown in the vertex form. If there was a number outside he bracket showing squares then you would get

    y = (-x + 4) ^2 + 4 (drawn in blue)

    y = (-x + 4) ^2 - 6 (drawn in green)

    These two examples show what the vertex form would look like if the axis was cut in 2 places or no places and there would be no solution for the first one and 2 places for the second one.
  2. 4 October, 04:57
    0
    It has 2 solutions

    1. y = - 1

    2. y = 4/3 = 1.333
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