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12 August, 21:20

What is the value of root 12+root 12+root12 ...

... to infinite

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  1. 12 August, 23:34
    0
    X=root (12+root (12+root ( ...)))

    x^2=12+root (12+root (12+root ( ...)))

    x^2=12+x

    x^2-x-12=0

    (x+3) (x-4) = 0

    X=4
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