Ask Question
11 December, 18:02

Can anyone explain how to differentiate this? (2x^2+3) sin5x

+1
Answers (1)
  1. 11 December, 19:41
    0
    Hello,

    (u*v) '=u'v+uv'

    u=2x²+3 = = > u'=4x

    v=sin 5x = = >v'=cos 5x * 5

    ((2x²+3 sin (5x)) '=4x * sin (5x) + (2x²+3) * cos (5x) * 5
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “Can anyone explain how to differentiate this? (2x^2+3) sin5x ...” in 📙 Mathematics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers