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10 August, 13:40

Jake has two similar cylindrical pipes. The radius of the first cylindrical pipe is 5 cm. The circumference of the second cylindrical pipe is 20 pi cm. The volume of the second cylindrical pipe is how many times greater than the volume of the first cylindrical pipe?

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  1. 10 August, 17:36
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    V=hpir^2

    c=2pir

    assuming they havve same height

    first one is

    v=hpi5^2

    v=25hpi

    2nd one

    c=2pir=20pi

    2pir=20pi

    2r=20

    r=10

    v=hpir^2

    v=hpi10^2

    v=100hpi

    big/small=100hpi/25hpir=4

    4 times greater
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