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Mathematics
Rosemary Montoya
7 January, 19:09
How do you solve log_8 5 - log_8 (x-6) = 1?
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Kaitlyn
7 January, 21:32
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Log₈ 5-log₈ (x-6) = 1
1)
log_a b - log_a c=log_a b/c
log₈ 5 / (x-6) = 1
2)
log_a b=c ⇔ a^c=b
log₈ 5 / (x-6) = 1 ⇔ 8¹ = 5 / (x-6)
8 (x-6) = 5
8x-48=5
8x=5+48
8x=53
x=53/8
Answer: x=53/8
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