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7 January, 19:09

How do you solve log_8 5 - log_8 (x-6) = 1?

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  1. 7 January, 21:32
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    Log₈ 5-log₈ (x-6) = 1

    1)

    log_a b - log_a c=log_a b/c

    log₈ 5 / (x-6) = 1

    2)

    log_a b=c ⇔ a^c=b

    log₈ 5 / (x-6) = 1 ⇔ 8¹ = 5 / (x-6)

    8 (x-6) = 5

    8x-48=5

    8x=5+48

    8x=53

    x=53/8

    Answer: x=53/8
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