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22 September, 14:17

The numerator of a fraction (which is in its simplest form) is 5 less than the denominator. If the numerator is multiplied by 2, and the denominator is increased by 16, then the fraction becomes smaller by 1/3 of it. Find the original fraction.

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  1. 22 September, 16:40
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    N = d - 5

    2n / (d + 16) = n/d - 1/3 n/d

    2n / (d + 16) = 2/3 n/d Divide by 2n

    1 / (d + 16) = 1/3 d

    Here's the tricky part.

    d + 16 = 3d the two denominators are equal. the numerators are both 1.

    16 = 2d

    d = 8

    so the numerator is d - 5

    n = 8 - 5

    n = 3

    Let's see if it checks out.

    n = 3

    d = 8

    2*3 = 6

    8 + 16 = 24

    New fraction 6/24 = 1/4

    (3/8 - 1/3) = 1/8

    3/8 - 1/8 = 1/4 so it checks with the original conditions put on it.
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