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9 July, 11:19

Solve for the interval 2sin (2x) = 1

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  1. 9 July, 14:41
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    Hello:

    2sin (2x) = 1

    sin (2x) = 1/2

    sin (2x) = sin (π/6)

    (2x = π/6 + 2kπ) or (2x = π-π/6 + 2k π) ... k in Z

    (x = π/12 + kπ) or (x = 5π/12 + kπ)
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