Find the axis of symmetry of the graph of the function.

f (x) = 2x2 - 16x + 27

A. x = - 3

B. x = 4

C. x = - 5

D. x = 6

Question

Karla

10 February, 12:27

+2

Answers (2)

Know the Answer?

Darien Watts · Answer 1

For f (x) = ax^2+bx+c

the axis of symmetry is - b/2a

f (x) = 2x^2-16x+27

a=2

b=-16

-b/2a = - (-16) / 2 (2) = 16/4=4

x=4

B is answer

Jaylen Barrett · Answer 2

X will be equal to 4. So, the right answer is B.

Find the axis of symmetry of the graph of the function.f (x) = 2x2 - 16x + 27A. x = - 3B. x = 4C. x = - 5D. x = 6