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10 February, 12:27

Find the axis of symmetry of the graph of the function.

f (x) = 2x2 - 16x + 27

A. x = - 3

B. x = 4

C. x = - 5

D. x = 6

+2
Answers (2)
  1. 10 February, 14:11
    0
    For f (x) = ax^2+bx+c

    the axis of symmetry is - b/2a

    f (x) = 2x^2-16x+27

    a=2

    b=-16

    -b/2a = - (-16) / 2 (2) = 16/4=4

    x=4

    B is answer
  2. 10 February, 14:32
    0
    X will be equal to 4. So, the right answer is B.
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