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6 October, 06:04

A ball is dropped from a height of 16 feet. each time it is drops, it rebounds 80% of the height from which it is falling fine the total distance traveled in 15 bounces

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  1. 6 October, 07:28
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    16+2*16 * (0.8) * [ (1 - (0.8) ^15) / (1-0.8) ]=139.5ft
  2. 6 October, 07:56
    0
    Notice total distance is comprised of both positive movements and negative movements, and both sequences are geometric (exponential) sequences ...

    The sum of a geometric sequence is:

    s (n) = a (1-r^n) / (1-r), a=initial term, r=common ratio, n=term number

    So for the "dropping" distances you have the sum ...

    s (n) = 16 (1-.8^n) / 0.2=80 (1-.8^n)

    s (15) = 80 (1-.8^15)

    And the "rising" distances you the first term is. 8 (16) = 12.8 and n=14 so

    s (14) = 12.8 (1-.8^14) / (.2)

    s (14) = 64 (1-.8^14)

    So the total distance traveled is:

    80 (1-.8^15) + 64 (1-.8^14)

    138.37050046578688

    Total distance is approximately 138.37 ft
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