Two forces act on a hook. the magnitude are F1=300N toward the positive x-axis and F2=125N at a 48 degree angle to the x-axis. find the direction and the magnitude of the resultant force?

Horizontal components:

F1x = 300

F2x = 125 * cos (48) = 83.64132579

horizontal net force:

Fx = 83.64132579 + 300

Fx = 383.6413258 N

Vertical components:

F2y = 125 * sine (48) = 92.89310318

vertical net force:

Fy = 92.89310318

Magnitude of the resulting force:

F = root ((Fx) ^ 2 + (Fy) ^ 2)

F = root ((383.6413258) ^ 2 + (92.89310318) ^ 2)

F = 125

Angle:

theta = Atan (Fy / Fx)

theta = Atan (92.89310318 / 383.6413258)

theta = 13.61 degrees

Answer:

The direction and the magnitude of the resultant force are:

F = 125 N

theta = 13.61 degrees