A cylinder is full at 471 cm³ and has a radius of 5 cm. It currently contains 314 cm³ of water.

What will the difference in the height of the water be when the cylinder is full?

Use 3.14 to approximate pi.

Question

Mathematics

Oswaldo

18 July, 09:16

A cylinder is full at 471 cm³ and has a radius of 5 cm. It currently contains 314 cm³ of water.

What will the difference in the height of the water be when the cylinder is full?

Use 3.14 to approximate pi.

+1

Answers (1)

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Alivia Stephens · Answer 1

So to start, you come up with equations for full volume and for the current volume. the volume of a cylinder is V=3.14r^2h and to find the height to start we plug in the radius (5) and the volume (471). 471=3.14 (25) h and solve for h. h=6 when it is full. Then, we do the same thing to the second one where the volume is 314 and the radius is obviously still 5. 314=3.14 (25) h and the height comes out to be 4. 6-4=2 so the difference between the two is 2.

A cylinder is full at 471 cm³ and has a radius of 5 cm. It currently contains 314 cm³ of water.What will the difference in the height of the water be when the cylinder is full?Use 3.14 to approximate pi.

A cylinder is full at 471 cm³ and has a radius of 5 cm. It currently contains 314 cm³ of water.

What will the difference in the height of the water be when the cylinder is full?

Use 3.14 to approximate pi.