Use successive differences to classify the function represented in the table. Show all your work.

X - 2 - 1 0 1 2

h (x) 14 5 2 5 14

Kinda confused ... per usual.

Since the third row is constant, we know that the function h is quadratic. Say h (x) = ax^2 + bx + c. Using h (0) = 2 = a (0) ^2 + b (0) + c, h (1) = 5 = a (1) ^2 + b (1) + c, and h (2) = 14 = a (2) ^2 + b (2) + c, we find a = 3, b = 0, and c = 2, so h (x) = 3x^2 + 2. same as computing a bunch of slopes only the denomintor is always so just the difference in the numerators - 10+29=19 - 3+10=7 - 2+3=1 - 1+2=1 6+1=7 25-6=19 the recessive differences are quadratic, to the original function is "other" namely cubic y=x^3-2 will work if you try the pairs