If A+D=117kg, A+M=88kg and M+D=161kg whats there total weight

thx in advance

Think of A as a constant - with D it's 117 and with M it's 88

So the difference between D and M is 29 (117-88)

We also know that M + D = 161

Let's substitute in the problem We will leave M equal to M and rewrite D as M+29 since it is 29 kg heavier.

M + M + 29 - 161 or 2M + 29 = 161 Subtracting 29 from both sides we get 2M=122

Now divide both sides two and get M=61

Since D is M+29 it is 61+29 or 100kg

Finally A + M = 88 A + 61 - 88 Subtract 61 from both sides and get A=17

So there you have it:

A=17kg

M=61kg

D=100kg and it works in all three equation in your problem (try it to check)

There's actually a really slick solution to this problem. Add all three equations. This results in 2 (A+M+D) = 366. Dividing by two, we see that A+M+D=183, so 183 is the total of the weights.