Simplify 5 log2 k - 8 log2 m + 10 log2 n.

A. 7 log2 (k - m + n)

B. 7 log2 kn over m

C. log2 50 kn over 8 m

D. log2 k to the fifth power n to the tenth power / m to the eighth power

The numerical coefficients of the logarithm are originally, the exponents of the variables. Such that,

log₂k⁵ - log₂m⁸ + log₂n¹⁰

Then the addition means we multiply them and subtraction means divide. The final answer would be,

log (k⁵n¹⁰/m⁸)