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4 August, 02:47

Explain how to resolve this problem. there are 13 books. some books cost $9 each and the rest cost $8 each. A total of $108 spent for all 13 books. how many $8 books were on the table.

the answer is actually 9. nine $8 books totals $72 and four $9 books total $36. $72+$36=$108. and 9+4=13 books

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Answers (2)
  1. 4 August, 04:43
    0
    X=one type that cost 9

    y=one type that cost 8

    total books=type1+type2

    total books=13

    x+y=13

    the total cost=cost of each added together

    cost of each=number of books times cost per book

    total cost=108

    9x+8y=108

    we have

    x+y=13

    9x+8y=108

    solve for x and y

    multiply first equation by - 8 and add to first equation

    -8x-8y=-104

    9x+8y=108 +

    x+0y=4

    x=4

    subsitute

    x+y=13

    4+y=13

    minus 4

    y=9

    4 of the $9

    9 of the $8

    thats how to solve
  2. 4 August, 05:10
    0
    The ancwer is 9. nine $8 books.
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