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15 December, 11:55

A teacher had 21 red pens. if the ratio of red pens to blue pens she owned was 3:1, how many pens did she have in total

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  1. 15 December, 13:22
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    She had 21:7 because if you multiply 3:1 by 7 each it is 21:7 so she had 7 blue pens
  2. 15 December, 14:37
    0
    There are 21 red pens. For every 3 red pens, there is 1 blue pen.

    Let's make these into a fraction equation.

    21/p=3/1

    p is the number of blue pens we have yet to find.

    First, cross multiply.

    21x1=21

    px3=3p

    Now, we have an equation of

    21:3p

    We set it equal to 1, and we solve it.

    21:3p = 1

    (21:3p) * 3p=1*3p

    21=3p

    21:3 = (3p) : 3

    7=p

    So, if there are 21 red pens, there are 7 blue pens.

    We add these together to find the total number of pens the teacher has.

    21+7=28

    The teacher has 28 pens total.
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