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Mathematics
Theodore Monroe
21 January, 16:38
2x-3y=31
3x+2y=1
Solve by elimination method
+3
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2
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Jayleen Rodgers
21 January, 16:59
0
2x - 3y = 31 ⇒ 6x - 9y = 93
3x + 2y = 1 ⇒ 6x + 4y = 2
-5y = 91
-5 - 5
y = - 18 1/5
2x - 3 (-18 1/5) = 31
2x + 54 3/5 = 31
- 54 3/5 - 54 3/5
2x = - 24 3/5
2 2
x = - 12 3/10
(x, y) = (-12 3/10, - 18 1/5)
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Linda Ferrell
21 January, 18:08
0
So,
Let's eliminate the y's.
Multiply the first equation by 2
4x - 6y = 62
Multiply the second equation by 3
9x + 6y = 3
Add the two equations together
13x = 65
Divide both sides by 13
x = 5
Substitute in the second equation
3 (5) + 2y = 1
15 + 2y = 1
Subtract 15 from both sides
2y = - 14
Divide both sides by 2
y = - 7
Check
3 (5) + 2 (-7) = 1
15 + - 14 = 1
1 = 1 This checks.
2 (5) - 3 (-7) = 31
10 - - 21 = 31
10 + 21 = 31
31 = 31 This also checks.
S = { (5,-7) }
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