There are three consecutive even integers. half the sum of the second and third numbers is 65. what are the integers

3 consecutive even integers ... x, x + 2, and x + 4

1/2 (x + 2 + x + 4) = 65 ... multiply both sides by 2, canceling out 1/2

x + 2 + x + 4 = 65 * 2

2x + 6 = 130

2x = 130 - 6

2x = 124

x = 124/2

x = 62

x + 2 = 62 + 2 = 64

x + 4 = 62 + 4 = 66

so ur numbers are : 62,64,66 <==